How do you graph this? g (x) defined piecewise: 2 for x

Question

How do you graph this?


g (x) defined piecewise:
 2 for x <= -2
 -x for -2 < x < 1
 2 for x = 1
 -1/x for 1 < x < 2
 3 for x >= 2

anonymous · Answer

Yes I do!

anonymous · Answer

Can you draw it for me really fast?

anonymous · Answer

Wait so I figured out how to graph it but now I am having troubles trying to figure out if it is continuous at x=-2,1,2

anonymous · Answer

& if not where are the discontinuities at

anonymous · Answer

whats the definition of continuous?

anonymous · Answer

|dw:1378592577375:dw|

anonymous · Answer

I believe it looks something like this

anonymous · Answer

forms an unbroken whole; without interruption.

phi · Answer

I would not put an open circle at (-2,2).   The function is defined there

anonymous · Answer

^ because of this  2 for x <= -2

anonymous · Answer

oh so it is a value... oh ok

anonymous · Answer

same with (1,-1) ?

anonymous · Answer

So x=-2 is continuous and x=1 is cont and x=2 is jump disc

phi · Answer

the function has a value at (1,2)  so you put an open circle at (1,-1) 
the   < operator  means this -1/x for 1 < x < 2 does not define g(1)
so it is an open circle at the "edges"

the filled circle goes at (1,2)