Question

Write the Henderson-Hasselbalch equation for a solution of propanoic acid (CH3CH2CO2H, pKa = 4.874 ) using HA, A–, and the given pKa value in the expression.

Answer 1

The henderson hasselbalch equation is given by: \(\sf \color{red}{pH = pK_a + log\frac{[A^-]}{[HA]}}\) where [A\(^-\)] is the molar concentration of a conjugate base. and [HA] = molar concentration of some weak acid.

Now, you can start off by writing a chemical equation of propanoic acid and dissociation of it's hydrogen.

Can you try it now?