Question

Help! The question is attached!

Answer 1

Attempt to solve for x! (4,y) and (7,-6); slope:-4

Answer 2

\[\frac{ -6-y }{ 7-4 }=-4\]
\[\frac{ -6-y }{ 3 }=-4 \]

I just set it up like the normal slope equation, (y2-y1)/(x2-x1). Now just see if you can solve for y.

Answer 3

Olay, let me try it out for myself to see if I understand it

Answer 4

Alrighty.

Answer 5

Wait, I get -6 / 3 how did you get -4?

Answer 6

You said the slope = -4, right? Well, the result of (y2-y1)/(x2-x1) is slope. But we already have the slope, so I just set the equation equal to -4.

Answer 7

Ahhhhhh okay I see how you set it up!

Answer 8

And then you subtract the bottom, correct?

Answer 9

Yeah, which left me with
\[\frac{ -6-y }{ 3 }=-4 \]Would you know how to use that to solve for y?

Answer 10

My guess is that I multiply -6 and 3

Answer 11

Just multiply both sides by 3 to start.

Answer 12

That will cancel the 3 out of the denominator of the fraction.

Answer 13

So would it be 18+3y=-4

Answer 14

Nah. Okay, so we multiply both sides by 3 and it looks liek this:

\[\frac{ 3(-6-y) }{ 3 }=-4(3)\]From here, the 3's on the left cancel out and -4 and 3 multiplies to get:
\[-6-y = -12 \]
Kinda see why?

Answer 15

Yea aha I sorta do, it's because I got -18-3y=-12 when I multiplied it by 3

Answer 16

Yeah, but you dont multiply the -6 and the -y by 3. Because you have a 3 on top and bottom, they cancel out and become 1. That is the whole purpose of multiply by 3 is because itll get rid of the denominator. It's just like if we had:

\[\frac{ x }{ 3 }=3 \]Because x is divided by 3, to get it by itself we do the opposite operation and multiply by 3.





Same thing with our problem: