Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (katherinesmith):

Find side AC. Round your answer to the nearest hundredth.

OpenStudy (katherinesmith):

OpenStudy (psymon):

Do you know about sin, cos, and tan?

OpenStudy (katherinesmith):

yes

OpenStudy (psymon):

Do you have an idea which one of the 3 you would need to use for this problem?

OpenStudy (katherinesmith):

well i know the hypotenuse of side AC but i don't know any other side. so i guess either sin or cos?

OpenStudy (psymon):

Well, the question wants side AC, so you want to use the trig function that includes that hypotenuse and the missing AC side.

OpenStudy (katherinesmith):

so cos?

OpenStudy (psymon):

Yep. So you have cos(40) = x/3 where x represents the AC side we do not know.

OpenStudy (katherinesmith):

.766 = x/3 ?

OpenStudy (psymon):

Its usually best to get the x by itself first if possible. It makes the answer a slight bit more accurate.

OpenStudy (katherinesmith):

how am i supposed to do that

OpenStudy (psymon):

Well, if you had x - 5 = 3, you would do the opposite and add by 5, right?

OpenStudy (katherinesmith):

x = cos40/3 ?

OpenStudy (psymon):

You did the wrong operation. x/3 is divison by 3, so you want to do the opposite of division.

OpenStudy (katherinesmith):

so x = 3/cos40

OpenStudy (psymon):

How did cos(40) get on bottom? :P So we have: \[\cos(40) = \frac{ x }{ 3 } \]So when we want x by itself, we have to do opposite operations. So since we have a division of 3, we want to multiply both sides by 3 \[(3)(\cos40) = \frac{ (3)x }{ 3 }\implies 3\cos40 = x \] Kinda make sense?

OpenStudy (katherinesmith):

lol i had that when i said .766 = x/3. the next step was that.

OpenStudy (katherinesmith):

the answer is 2.29

OpenStudy (psymon):

Right. I just meant to say that doing the multiplication of 3 first is usually more accurate. If you put 3cos(40) on your calculator, it comes out a bit more accurate then if you do cos40 = .766 then times 3. Its just a good habit I suppose xD But yeah, looks right :p So that is your side AC.

OpenStudy (katherinesmith):

okay. i have a few other questions, if i post them would you be willing to help me?

OpenStudy (psymon):

Yeah, sure.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!