Question

cot((x - (pi/2)) = -tan x

Answer 1

\[
\cot (x-\pi/2) = \frac{\cos(x-\pi/2)}{\sin(x-\pi/2)}
\]

Answer 2

what do i do with this?

Answer 3

Remember \[
\cos(\pi/2-x) = \sin(x)
\]

Answer 4

ok so is that the answer? or do i have to do something else?

Answer 5

You have to keep manipulating it until it becomes what you want it to be.

Answer 6

so do i foil it?

Answer 7

Okay so \(x-\pi/2 = -(\pi/2-x)\)

Answer 8

\[
\cos(-x) = \cos(x) \quad \sin(-x) = -\sin(x)
\]