Question

what is the answer of cot/cos ;csc

Answer 1

\[\frac{\cot x}{cosx}=\frac{\cos x}{\sin x}*\frac{1}{cosx}=\frac{1}{sinx}=cscx\]

Answer 2

That was amazing @Luigi0210 !

Answer 3

Naw, pretty simple/basic if you ask me :3

Answer 4

That was supposed to be sarcastic XD

Answer 5

I see >.>

Answer 6

nice one luigi thank you for your answer

Answer 7

how about this what is the answer 1+cot^2 theta /sec ^2 theta ; Cot ^2 theta

Answer 8

I'll wait for DLS :3

Answer 9

\[\LARGE \frac{1+\cot^2 \theta} {\sec ^2 \theta}=\frac{cosec^2 \theta}{\sec^2 \theta}=\frac{\frac{1}{\sin^2 \theta}}{\frac{1}{\cos^2 \theta}}=\]

Answer 10

phew,this was tough :3

Answer 11

\[\Huge 1+\cot^2 \theta=cosec^2 \theta\]
iis the property here

Answer 12

that is the final answer?

Answer 13

\[\LARGE \frac{1+\cot^2 \theta} {\sec ^2 \theta}=\frac{cosec^2 \theta}{\sec^2 \theta}=\frac{\frac{1}{\sin^2 \theta}}{\frac{1}{\cos^2 \theta}}=\]
u cant solve it now??

Answer 14

The final answer can be found deep within your soul.. you just have to look deep enough xD

Answer 15

ah ok but we don't have any give that is the only given

Answer 16

(1+cos theta) (1-cos theta) ; sin ^2 theta

Answer 17

@luigi0210 ? :P

Answer 18

you wanna do it?

Answer 19

@frincess use this property
\[\LARGE (a+b)(a-b)=a^2-b^2\]

Answer 20

DLS ur so smart in math

Answer 21

Oh, yea give me the headache problem >.>
Distribute and you get:
\[(1-\cos^2x)=\sin^2x\]

Answer 22

\[\Huge \cos^2 \theta+\sin^2 \theta=1\]
is the property here

Answer 23

why is all this happening on OS feedback BTW?

Answer 24

1+tan^2theta/ csc^2 : tan^2 theta

Answer 25

\[\Huge 1+\tan^2 \theta=\sec^2 \theta\]
is the property here

Answer 26

how did u get that can u tell me how to get a solution

Answer 27

One question at a time D:

Answer 28

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SIR OR MADAM. please post the Question in the correct Section.

Answer 29

Folks the proper place for this question is in Math. Next time....

Answer 30

its a standard property @frincess and yet again I advice you to post in the MATH section

Answer 31

It wasn't me Preetha >.>

Answer 32

@Preetha already posted :D

Answer 33

http://openstudy.com/study#/groups/Mathematics
@frincess

Answer 34

oh in mathematics
who is engineering her