A ball is thrown vertically upward from the ground at a velocity of 150 feet per second. Its distance from the ground after t seconds is given by How fast is the ball moving 10 seconds after being thrown?
so we know that \[v=v_{0}+at\]
yes velocity
or since this involves gravity our acceleration is constant so we have\[v=v _{0}-g t\]
velocity = increment - gravity * time?
so you would plug in the givens of 10s and initial velocity of 150ft/s which converts to about 45m/s
and you have v=45-10*10
velocity equals velocity initial times gravity time time
times*
oh so it is velocities starting value
v0
you are missing the "is given by" rule .... which then would have its derivative taken
yes
Its distance from the ground after t seconds is given by _______
ft
given in feet lol
toadill he is talking about how the question in the beginning says is given by and then it goes right to the next sentence of "How fast is..."
How fast is the ball moving 10 seconds after being thrown
recons physics formula is apt :)
apt?
yeah more errors
apt: appropriate or suitable in the circumstances.
I am just trying to review this is what the instructor gave me lol
\[h(t) = -\frac12gt^2+v_ot+h_o\] \[h'(t) = v(t)\] \[v(t)=-gt+v_o\]
by s(t) = -16t^2 + 150ft
I guess it was an image instead of text.
yeah, those copy pastes get eaten sometimes if they cant be processed correctly :)
s(t) = -16t^2 + 150t , the derivative of displacement is velocity
So you just find the derivative of the function?
yes, and plug in t=10 for the solution
okay thanks I am going to take a break now.
margarita ville?
yeah lol
:) enjoy
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