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Mathematics 7 Online
OpenStudy (anonymous):

What is the graph of the absolute value inequality? Graphs attached y < |x + 2| - 2

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

It's either the first or 3rd...

ganeshie8 (ganeshie8):

find the vertex first

OpenStudy (anonymous):

-2 is the vertex

ganeshie8 (ganeshie8):

Yes, first or 3rd, very good observation :)

OpenStudy (anonymous):

+2 is the slope...

ganeshie8 (ganeshie8):

we dont need to bother about slope here. vertex = (-2, -2)

OpenStudy (anonymous):

The first :)

ganeshie8 (ganeshie8):

now look at first & 3rd graphs which one has vertex at (-2, -2) ?

ganeshie8 (ganeshie8):

omg ! you're super fast :)) yes its the first one :)

OpenStudy (anonymous):

Help me with my final graph?

ganeshie8 (ganeshie8):

sure, post :)

OpenStudy (anonymous):

Write the inequality for the graph -6x + 5y >= -30 -6x + 5y <= -30 5x - 6y <= -30 5x - 6y >= -30

ganeshie8 (ganeshie8):

look at the graph, it has y intercept of 5 that means, when x=0, y = 5

ganeshie8 (ganeshie8):

now look at the equations, and can u strike off few equations ?

OpenStudy (anonymous):

It's the 2nd equation :)

ganeshie8 (ganeshie8):

nopes. careful :)

ganeshie8 (ganeshie8):

its not first and second equations cuz, when we put x = 0, they DONT give y intercept of graph

OpenStudy (anonymous):

Then it has to be the third since it's shaded below the line

ganeshie8 (ganeshie8):

nopes. its the fourth one actually

ganeshie8 (ganeshie8):

dont discout the negatives :)

ganeshie8 (ganeshie8):

fourth inequation :- 5x - 6y >= -30 change it to point slope form

ganeshie8 (ganeshie8):

5x - 6y >= -30 -6y >= -5x - 30 -y >= -5/6x - 5

ganeshie8 (ganeshie8):

now, multiply the whole inequation wid -1, when u multiply a negative number, >= becomes <=

ganeshie8 (ganeshie8):

5x - 6y >= -30 -6y >= -5x - 30 -y >= -5/6x - 5 y <= 5/6x + 5

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