Mathematics
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OpenStudy (anonymous):
What is the graph of the absolute value inequality? Graphs attached
y < |x + 2| - 2
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OpenStudy (anonymous):
OpenStudy (anonymous):
OpenStudy (anonymous):
It's either the first or 3rd...
ganeshie8 (ganeshie8):
find the vertex first
OpenStudy (anonymous):
-2 is the vertex
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ganeshie8 (ganeshie8):
Yes, first or 3rd, very good observation :)
OpenStudy (anonymous):
+2 is the slope...
ganeshie8 (ganeshie8):
we dont need to bother about slope here.
vertex = (-2, -2)
OpenStudy (anonymous):
The first :)
ganeshie8 (ganeshie8):
now look at first & 3rd graphs
which one has vertex at (-2, -2) ?
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ganeshie8 (ganeshie8):
omg ! you're super fast :)) yes its the first one :)
OpenStudy (anonymous):
Help me with my final graph?
ganeshie8 (ganeshie8):
sure, post :)
OpenStudy (anonymous):
Write the inequality for the graph
-6x + 5y >= -30
-6x + 5y <= -30
5x - 6y <= -30
5x - 6y >= -30
ganeshie8 (ganeshie8):
look at the graph, it has y intercept of 5
that means, when x=0, y = 5
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ganeshie8 (ganeshie8):
now look at the equations, and can u strike off few equations ?
OpenStudy (anonymous):
It's the 2nd equation :)
ganeshie8 (ganeshie8):
nopes. careful :)
ganeshie8 (ganeshie8):
its not first and second equations
cuz, when we put x = 0, they DONT give y intercept of graph
OpenStudy (anonymous):
Then it has to be the third since it's shaded below the line
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ganeshie8 (ganeshie8):
nopes. its the fourth one actually
ganeshie8 (ganeshie8):
dont discout the negatives :)
ganeshie8 (ganeshie8):
fourth inequation :-
5x - 6y >= -30
change it to point slope form
ganeshie8 (ganeshie8):
5x - 6y >= -30
-6y >= -5x - 30
-y >= -5/6x - 5
ganeshie8 (ganeshie8):
now, multiply the whole inequation wid -1,
when u multiply a negative number, >= becomes <=
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ganeshie8 (ganeshie8):
5x - 6y >= -30
-6y >= -5x - 30
-y >= -5/6x - 5
y <= 5/6x + 5