Question

I am a little stuck on part b. The question shows a picture of a mass spectrum for 1-bromopropane. It then has the following questions:
3a) Identify the species responsible for signals m/z 124, 122, 81, 79, 43 and 29. (Completed)
3b) Write an equation for the formation of each species:
So far i have gotten
C3H7Br -> [C3H7]^+ +Br(radical) + e-
But i am unsure about the rest.
Any feedback is greatly appreciated! :)

Answer 1

The question starts with 1-bromopropane so I am unsure about the fragments

Answer 2

That means you have:

Answer 3

I am confused as how that links into the question as it is to do with peaks on a mass spectrum graph, would it be more helpful if i posted a picture of the question?

Answer 4

as to**

Answer 5

the formation of 1-bromopropane?

Answer 6

That is the whole question

Answer 7

Yes, well each mass corresponds to the intermediate steps towards the formation. Such as cation formation...and so forth.

Answer 8

yes so for example [C3H7]+ would be 43

Answer 9

and 29 would be [C2H5]+

Answer 10

Yes.

Answer 11

The point i get confused at is when you have to write the whole equation, i can get the fragments but not the rest of the equation. So one of the equations would be:
C3H7Br --> [C3H7]+, + Br(radical) + e-
But what would it be if the fragment was [C3H6Br]+ then what would the other products be?

Answer 12

Would it be [C3H6Br]+ + an e-? or would there be other products too?