6-9/7x>8
\(6-\dfrac{9}{7}x>8\) If this were an equation instead of an inequality, would you know how to solve it?
no bc im not good with fractions but this is what i got x<1 1/5
Ok, I can help you. Give me a minute to solve it.
The first step will be to move the constant term (6) to the right by using inverse operations - because it is positive, you will subtract 6 from both sides.
What did you get from that step?
-9/7x>2
Great! Now you want to separate the fraction from the x term. You will do that by dividing both sides by -9/7. Two things to remember: 1. When you divide an inequality by a negative - the inequality reverses. (I think you already knew that) 2. When you divide by a fraction, you actually multiply by its inverse.
FYI: \(8\div 2 = 8 \times \dfrac{1}{2}\) \(\dfrac{1}{2}\) is the inverse of 2
Your next step in this inequality will look like this: \(-\dfrac{9}{7}\div-\dfrac{9}{7}x >2 \div -\dfrac{9}{7}\)
Same \(\implies\) Change \(\implies\) Flip Keep the first fraction the same, change the division to multiplication, flip the second fraction. Give that a try and let me know what you get.
x<1 1/5
Not quite.
On the left side, the fractions will cancel out - on the right side, you multiply straight across: \(-\dfrac{9}{7}\times-\dfrac{7}{9}x < 2 \times -\dfrac{7}{9}\)
-14/9
Yes. You probably need to answer in simplest terms, so that would mean to change the improper fraction to a mixed number.
1 1/9 would be the answer
Yes, that is the answer I got. Except that it is still negative. Got to watch out for those pesky negatives, they are slippery and tend to fall on the floor. :-)
Do you understand the answer? Would you like more help with fractions?
thank you so much!
You're welcome.
if this was an inequality would i flip the sign
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