Question

solve 1/4^(x+1) = 8x?

Answer 1

Is this it?

\( \left( \dfrac{1}{4} \right) ^{x + 1} = 8x\)

Answer 2

yesss

Answer 3

I don't understand...:(

Answer 4

Is the right side correct. It's 8x, not 8^x?

Answer 5

whoops its 8^x, sorry

Answer 6

That's better.

Answer 7

\( \left( \dfrac{1}{4} \right)^{x + 1} = 8^x\)

Rewrite the left side as a power of 2.
Rewrite the right side as a power of 2.

Answer 8

how do I do that?

Answer 9

\( \left( \dfrac{1}{4} \right) ^ {x + 1} = 8^x\)

Start like this. Now multiply the exponents together on each side.

\( \left( 2^{-2} \right) ^ {x + 1} = (2^3)^x\)

Answer 10

x=-2/5?

Answer 11

\(\left( 2^{-2} \right) ^ {x + 1} = (2^3)^x\)

\( 2^{-2x -2} = 2^{3x} \)

\( -2x -2 = 3x \)

\( -5x = 2 \)

\(x = -\dfrac{2}{5} \)

You are correct.

Answer 12

yes! thanks :D

Answer 13

wlcm