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Mathematics 8 Online
OpenStudy (anonymous):

lim x→0 (sin⁴ x)/x

OpenStudy (anonymous):

L'Hopital's rule will work here.

OpenStudy (anonymous):

Or, more simply, use the rule that the limit of the product is the product of the limits.\[\lim_{x→0 }\frac{ (\sin⁴ x)}{x}=\lim_{x→0 }\sin^3x \lim_{x→0 }\frac{ (\sin x)}{x}=0\]

OpenStudy (anonymous):

Recall that \[\lim_{x \rightarrow 0}\frac{sinx}{x}=1\]

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

so should it be 1⁴?

OpenStudy (anonymous):

No. How did you get that?

OpenStudy (anonymous):

well the identity gives us one

OpenStudy (anonymous):

Yeah, but the other limit \[\lim_{x \rightarrow0}\sin^3x =0\] is also a factor, and sends the limit of the product to zero. One times zero is zero.

OpenStudy (anonymous):

oh I follow now

OpenStudy (anonymous):

No sweat. Do math every day.

OpenStudy (anonymous):

thank you, I just didn't know I could separate to make that identity thanks a lot for your help

OpenStudy (anonymous):

Just remember the rules, and figure out how to make the problem look like something that you can solve.

OpenStudy (anonymous):

dually noted. thanks again.

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