can someone please help me with this? its making my head explode because I am not sure if you need to use the method of substitution. what is the point of intersection? y=-2x 2x+3y=-12
Use it anyway!
If you don't know how to do it, then use the method you know!
Math Rule #159: Do what you know works.
yeah but will that give me my intersection?
The point of intersection is basically the values of x and y.
So if \(x=a\) and \(y=b\) this means the point of intersection is \((a,b)\).
solving 2 equations like this with algebra is the same thing as finding where two lines intersect.
oh okay because my answer was 0,-6 and I think that's wrong
when x is 0, the first equation gives you y=0 which is not -6 your solution has to work for both equations
try again y=-2x 2x+3y=-12 replace y with -2x in the 2nd equation 2x + 3(-2x) = -12 can you simplify this ?
x=-4
-3
x=3
are you guessing ? the first thing is simplify 3*-2*x to -6x in 2x + 3(-2x) = -12 to get 2x -6x = -12 now you have 2 x's takeway 6 x's. how many x's do you have ?
-4x
so you have -4x= -12 divide both sides by -4 -4x/-4 = -12/-4 on the left, -4/-4 is 1, and 1x is x x = ?
-3
3
minus divided by minus makes a plus -12/-4 is +3 x= 3 now find y using y=-2x (replace the x with 3 to find y )
your really good thank you very much
yw
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