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Chemistry 6 Online
OpenStudy (tgoddard):

Gallium is composed of two naturally occurring isotopes: Ga-69 (60.108%) and Ga-71 . The ratio of the masses of the two isotopes is 1.0290. What is the mass of Ga-69

OpenStudy (aaronq):

atomic mass = \(\Sigma (i_{\%abundance}*Ga^{i})\) atomic mass = % abundance(1) * isotope(1) +% abundance(2) * isotope(2)+....

OpenStudy (tgoddard):

I have the values of Ga-69 as .618511, and Ga-71 as .410489, the percent for Ga-71 is 39.892%. I keep getting 1.029 for the mass of Ga-69. Using this, I came up with .618511 g. I know I am doing something wrong...

OpenStudy (aaronq):

sorry i misread the question ratio = 1.0290 = \(\dfrac{Ga^{71}}{Ga^{69}}\) are you allowed to use the actual molar mass of Ga?

OpenStudy (aaronq):

1.029*\(Ga^{69}=Ga^{71}\) 69.723 amu = 60.108% \(Ga^{69}\)+ (41.0489%)*1.029*\(Ga^{69}\)

OpenStudy (aaronq):

i got x=68.1239150124833732

OpenStudy (tgoddard):

Yes we can use actual molar mass

OpenStudy (aaronq):

do you understand what i did above?

OpenStudy (tgoddard):

I think so, give me a second to run some numbers with it

OpenStudy (tgoddard):

the second percentage is supposed to be 39.892 I believe

OpenStudy (aaronq):

sorry, you're right about that, i copied the numbers you posted earlier. So yeah, change that in the equation.

OpenStudy (tgoddard):

Thank you

OpenStudy (aaronq):

no problem

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