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Chemistry 11 Online
OpenStudy (anonymous):

Please help... A student in lab creates a Beer's Law calibration curve with the equation A=7.02M-1c. What is the concentration of the solution if the absorbance is 0.327?

OpenStudy (anonymous):

I don't know if I should use this equation which is given: A=7.02M-1c. Since the absorbance is 0.327, I put that in for (A) and we are looking for the concentration (c). 0.327=7.02M-1c 0.327/7.02M-1=7.02M-1c/7.02M-1 0.04658=0.0466

OpenStudy (aaronq):

what does M stand for?

OpenStudy (anonymous):

Molarity

OpenStudy (aaronq):

that is how you would solve it though. if M is molarity, then what is C?

OpenStudy (anonymous):

concentration

OpenStudy (aaronq):

but Molarity IS concentration.. why is there 2 units of concentration?

OpenStudy (anonymous):

That is what was given to us.

OpenStudy (anonymous):

I think my calculation is correct

OpenStudy (aaronq):

i mean, the way you're solving it seems right, but i don't think M would stand for molarity, IF, C is concentration.

OpenStudy (anonymous):

You are right. I'm guessing my units are in s-1

OpenStudy (aaronq):

the answer can't be in units of 1/s, you're finding concentration :S

OpenStudy (anonymous):

Could it be in grams?

OpenStudy (aaronq):

could be in g/L but not just grams, thats a unit of mass not conc.

OpenStudy (anonymous):

Thanks. I need to get it together for real. Thanks for the help and explanation.

OpenStudy (aaronq):

no worries! good luck

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