Question

(1/r) + (r/(2-r))=-7/4 How do you solve this??

Answer 1

to add fractions, their denominators must be the same. to do so we will force it by multiplying by the missing term(s). notice that were really just multiplying by one.

\[\frac{ 1 }{ r } + \frac{ r }{ 2-r } = \frac{ 7 }{ 4 }\]\[\frac{ 1 }{ r }\times \frac{ 2-r }{ 2-r } + \frac{ r }{ 2-r } \times \frac{ r }{ r } = \frac{ 7 }{ 4 }\]\[\frac{ 2-r }{ r(2-r) } + \frac{ r^2 }{ r(2-r) } = \frac{ 7 }{ 4 }\]\[\frac{ 2-r + r^2 }{ r(2-r) } = \frac{ 7 }{ 4 }\]\[2-r+r^2 = \frac{ 7 }{ 4}\left( r(2-r) \right)\]

and solve from here. probably best using the quadratic formula.

let me know if you have follow-up questions ^_^

Answer 2

Wait May you type it using the equation generator I don't really understand what youutypes D;

Answer 3

i did use it.

refreshing page might fix it

Answer 4

mhm yea seems to not show up :\

Answer 5

\[x^2 = \pi\]

do you see this as proper latex?

are you blocking javascript with your browser?

Answer 6

hmhm yea that's what it seems

Answer 7

Would writing it out be better?