Can you please help me with this? This is part of an assignment that is due tonight.
genson0 If F is the focal length of a convex lens and an object is placed at a distance x from the lens, then its image will be at a distance y from the lens, where F, x, and y are related by the lens equation \[\frac{ 1 }{ F }=\frac{ 1 }{ x }+\frac{ 1 }{ y }\] Suppose that a lens has a focal length of 4.2 cm, and that the image of an object is 8 cm closer to the lens than the object itself. How far from the lens is the object?
Could you explain please? Sorry.
6.1cm doesn't seem to be write according to webassign.
the question is, what is "x" ? the information given is F= 4.2 and " image of an object is 8 cm closer to the lens than the object itself" which can be expressed as the equation y= x-8
substituting the given information into the given equation \[\frac{1}{4.2}= \frac{1}{x} + \frac{1}{x-8}\] from here, you just need to solve for x
Yes I got to this point, I am lost at this point. Please help.
combine the right side
what is the common denominator?
I am at this point \[\frac{ d(d-8) }{ 4.2d(d-8) }=\frac{ 4.2d -33.6 +4.2d }{ 4.2d(d-8 }\]
right, now get rid of the denominators
you if multiplied 4.2 d ( d- 8) to both sides, then the denominators would cancel out
then move everything to one side, at this point, you will have a 2nd degree polynomial equal to zero solve either by factoring or by using the quadratic equation
\[d^2-16.4d+33.6=0\] Alright this is where I dont know, I dont know any factor of 16.4 and 33.6
Are these the right numbers?
i have no idea, i dont have a piece of paper in front of me
assuming you didnt make a mistake earlier, the numbers seem fine
I'm lost at this point :/ I don't know what numbers to instert
quadratic equation for \[ax^2+bx+c = 0\] \[x= \frac{-b\pm \sqrt{b^2 - 4ac}}{2a}\]
OH how could i not think of that.
I got d=14, and d=2.4 So how do I get the answer? it asks for only one
They both work also into the equation.
y= x-8 which answer makes sense now?
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