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Atomic radius of Cu is greater than Cr but ionic radius of Cr2+ is greater than Cu2+ Why?
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compare the number of protons and electrons in each atom and ion. The difference in electron distributions makes all the difference
I don't get it. 29 protons holding 27 electrons in Cu 2+ ion 3d9, 4s0 configuration 24 protons holding 22 electrons in Cr 2+ ion 3d4, 4s0 configuration
that's exactly the reason. the imbalance of proton\electron pull of each nucleus determines which ion will have a larger radius
What's the difference in the pull in this case? I need a logical explanation
"What's the difference in the pull in this case?" If you want a quantitative answer, calculate \(Z_{eff}\) for valence e using slater's rules
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