Question

find the pattern for the sequence 384,192,96,48

Answer 1

each consecutive term is half of the previous
so the progression would be
\[T _{n} = 384 \times (\frac{ 1 }{ 2 })^{n-1} \]
where n is any given term is the sequence

Answer 2

for example
to find to third term:
\[T _{3}= 384 \times (\frac{ 1 }{ 2 })^{3-1}\]
\[T _{3}= 384 \times (\frac{ 1 }{ 2 })^{2}\]
\[T _{3}= 384 \times \frac{ 1 }{ 4 }\]
\[T _{3}= 96\]

Answer 3

thank you so much!!!