Question

Calculating Range of a function

Answer 1

\[f(x) = \sqrt{x-1}\]

Answer 2

I can do the domain but not the range

Answer 3

Help please @Luigi0210

Answer 4

I gtg so.. @austinL

Answer 5

Graph the function and look at the values that it takes of y.

Answer 6

I did that, but the problem said to solve for it first

Answer 7

??? I can solve for domain but not range

Answer 8

Find the derivative of the following via implicit differentiation:
d/dx(f(x)) = d/dx(x-1---(-(-sqrt(x))))
Rewrite the expression: d/dx(f(x)) = d/dx(f(x)):
d/dx(f(x)) = d/dx(-sqrt(x)+x)
The derivative of f(x) is f'(x):
f'(x) = d/dx(-sqrt(x)+x)
Differentiate the sum term by term and factor out constants:
f'(x) = d/dx(x)-d/dx(sqrt(x))
Use the power rule, d/dx(x^n) = n x^(n-1), where n = 1/2: d/dx(sqrt(x)) = d/dx(x^(1/2)) = x^(-1/2)/2:
f'(x) = d/dx(x)-1/(2 sqrt(x))
The derivative of x is 1:
f'(x) = -1/(2 sqrt(x))+1
Expand the left hand side:
Answer: |
| f'(x) = 1-1/(2 sqrt(x))

Answer 9

I don't know derivatives yet. sorry

Answer 10

Oh =(

Answer 11

I'll just close the question