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jimthompson5910 (jim_thompson5910):
for finding the distance between two points
jimthompson5910 (jim_thompson5910):
for instance, what is the distance from point F to point G?
OpenStudy (anonymous):
I don't know... ?
jimthompson5910 (jim_thompson5910):
use the distance formula
\[\large d = \sqrt{\left(x_{2}-x_{1}\right)^2+\left(y_{2}-y_{1}\right)^2}\]
to find out
OpenStudy (anonymous):
I don't feel like I'm inputting it correctly.
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jimthompson5910 (jim_thompson5910):
show me what you got so far
OpenStudy (anonymous):
do I use just one coordinate pair at a time?
jimthompson5910 (jim_thompson5910):
you use them both
jimthompson5910 (jim_thompson5910):
(x1,y1) is the first point
(x2,y2) is the second point
OpenStudy (anonymous):
yes.. but how can that work when there are 4 pairs of coordinates?
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jimthompson5910 (jim_thompson5910):
you do them a pair at a time
jimthompson5910 (jim_thompson5910):
so if you want to find the distance from F to G, you only focus on those two points
OpenStudy (anonymous):
can you input an example? I don't think you're understanding my question
jimthompson5910 (jim_thompson5910):
Let's make point F the first point
so that means
F(-6,-10) = (x1,y1)
which means
x1 = -6
y1 = -10
see how I'm getting this?
OpenStudy (anonymous):
d = sqrt(-6-10)^2 + (-10-2)^2?
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jimthompson5910 (jim_thompson5910):
so far, so good
jimthompson5910 (jim_thompson5910):
now simplify/evaluate
OpenStudy (anonymous):
Okay..can you check
jimthompson5910 (jim_thompson5910):
what did you get
OpenStudy (anonymous):
20
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jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
so that is the length of one side
luckily the opposite side is also 20 because this a rectangle (opposite sides of a rectangle are equal)
OpenStudy (anonymous):
okay.. now the same thing for the other coordinates?
jimthompson5910 (jim_thompson5910):
so you can think of it as the length of 20 units
jimthompson5910 (jim_thompson5910):
yes you need to find the width now
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OpenStudy (anonymous):
ok one sec
OpenStudy (anonymous):
d = sqrt(7-(-9)^2 + (6-(-6))^2
look okay for the first step?
jimthompson5910 (jim_thompson5910):
yes it does, keep going
OpenStudy (anonymous):
d = sqrt(x2-x1)^2 + (y2-y1)^2
d = sqrt(7-(-9)^2 + (6-(-6))^2
d = sqrt(16)^2 + (12)^2
d = sqrt(256)^2 + (144)^2
d = sqrt(65,536)+(20,736)
d = sqrt(86,272)
d = 293.720956
rounded: 293.7
jimthompson5910 (jim_thompson5910):
you're doing great until you hit this line d = sqrt(65,536)+(20,736)
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jimthompson5910 (jim_thompson5910):
it should be this
d = sqrt( 16^2 + 12^2 )
d = sqrt( 256 + 144 )
d = sqrt( 400 )
d = 20
jimthompson5910 (jim_thompson5910):
so the distance from point H to point I is 20 units
OpenStudy (anonymous):
ohhh hahaha whoops okay so from H to I is 20 and f to g is 20?
jimthompson5910 (jim_thompson5910):
correct on both
jimthompson5910 (jim_thompson5910):
you just need two more sides
once you have the length of all 4 sides, you can add them up to get the perimeter
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OpenStudy (anonymous):
How do I get the other two?
jimthompson5910 (jim_thompson5910):
find the distance from G to H
OpenStudy (anonymous):
Why not F to I?
jimthompson5910 (jim_thompson5910):
that's another side length we'll get to
OpenStudy (anonymous):
d = sqrt(x2-x1)^2 + (y2-y1)^2
d = sqrt(10-7)^2 + (2-6)^2
d = sqrt(3)^2 + (-4)^2
d = sqrt(9) + (16)
d= sqrt(25)
d = 5
The distance from G to H is 5 units.
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jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
how about from F to I
OpenStudy (anonymous):
d = sqrt(x2-x1)^2 + (y2-y1)^2
d = sqrt(-6-(-9))^2 + (-10-(-6))^2
d = sqrt(3)^2 + (-4)^2
d = sqrt(9) + (16)
d = sqrt(25)
d = 5
The distance from F to I is 5 units.
jimthompson5910 (jim_thompson5910):
very good
jimthompson5910 (jim_thompson5910):
now add up the 4 sides to get the perimeter
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