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Mathematics 10 Online
OpenStudy (anonymous):

What is the mage of point D in figure ABCD for a dilation with a center of (0,0) and a scale factor of 2?

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

the figure is missing

OpenStudy (anonymous):

jimthompson5910 (jim_thompson5910):

what is point D?

OpenStudy (anonymous):

-2?

jimthompson5910 (jim_thompson5910):

as an ordered pair, where is point D?

jimthompson5910 (jim_thompson5910):

ie what are the coordinates of it? or its location?

OpenStudy (anonymous):

I don't know... that's why I'm asking for help.

jimthompson5910 (jim_thompson5910):

well you start at (0,0), which is the origin

jimthompson5910 (jim_thompson5910):

then you go to the left 1 unit then you go up 4 units to get to the point ________

OpenStudy (anonymous):

D

OpenStudy (anonymous):

wait, then you go left 1 after what?

jimthompson5910 (jim_thompson5910):

yes but where is point D ex: if you went to the right 1 and up 3, then you would be at the point (1,3)

OpenStudy (anonymous):

okay then I scale it by the factor of 2?

jimthompson5910 (jim_thompson5910):

yes but first tell me where point D is

jimthompson5910 (jim_thompson5910):

what is the (x,y) form of this point

OpenStudy (anonymous):

-3,4?

jimthompson5910 (jim_thompson5910):

close, but it's (-1, 4) you go over to the left 1, then up 4

OpenStudy (anonymous):

no.. nevermind.

jimthompson5910 (jim_thompson5910):

D is the point (-1,4)

OpenStudy (anonymous):

yeah.. I was looking at point A for one of the coordinates

jimthompson5910 (jim_thompson5910):

when you apply the scale factor of 2, you double each coordinate

OpenStudy (anonymous):

Okay it was what I though it was.

OpenStudy (anonymous):

Could you check my answer on another question?

jimthompson5910 (jim_thompson5910):

sure what do you need

OpenStudy (anonymous):

What is the perimeter of the rectangle with vertices F(-6,-10), G(10,2), H(7,6), and I(-9,-6)? My answer:

OpenStudy (anonymous):

2(w + h) 2(-6 + -10) = -32 2(10 + 2) = 24 2(7 + 6) = 26 (-9 + -6) = -30

jimthompson5910 (jim_thompson5910):

do you remember the distance formula?

OpenStudy (anonymous):

distance formula for what?

OpenStudy (anonymous):

I think so..

jimthompson5910 (jim_thompson5910):

for finding the distance between two points

jimthompson5910 (jim_thompson5910):

for instance, what is the distance from point F to point G?

OpenStudy (anonymous):

I don't know... ?

jimthompson5910 (jim_thompson5910):

use the distance formula \[\large d = \sqrt{\left(x_{2}-x_{1}\right)^2+\left(y_{2}-y_{1}\right)^2}\] to find out

OpenStudy (anonymous):

I don't feel like I'm inputting it correctly.

jimthompson5910 (jim_thompson5910):

show me what you got so far

OpenStudy (anonymous):

do I use just one coordinate pair at a time?

jimthompson5910 (jim_thompson5910):

you use them both

jimthompson5910 (jim_thompson5910):

(x1,y1) is the first point (x2,y2) is the second point

OpenStudy (anonymous):

yes.. but how can that work when there are 4 pairs of coordinates?

jimthompson5910 (jim_thompson5910):

you do them a pair at a time

jimthompson5910 (jim_thompson5910):

so if you want to find the distance from F to G, you only focus on those two points

OpenStudy (anonymous):

can you input an example? I don't think you're understanding my question

jimthompson5910 (jim_thompson5910):

Let's make point F the first point so that means F(-6,-10) = (x1,y1) which means x1 = -6 y1 = -10 see how I'm getting this?

OpenStudy (anonymous):

d = sqrt(-6-10)^2 + (-10-2)^2?

jimthompson5910 (jim_thompson5910):

so far, so good

jimthompson5910 (jim_thompson5910):

now simplify/evaluate

OpenStudy (anonymous):

Okay..can you check

jimthompson5910 (jim_thompson5910):

what did you get

OpenStudy (anonymous):

20

jimthompson5910 (jim_thompson5910):

good

jimthompson5910 (jim_thompson5910):

so that is the length of one side luckily the opposite side is also 20 because this a rectangle (opposite sides of a rectangle are equal)

OpenStudy (anonymous):

okay.. now the same thing for the other coordinates?

jimthompson5910 (jim_thompson5910):

so you can think of it as the length of 20 units

jimthompson5910 (jim_thompson5910):

yes you need to find the width now

OpenStudy (anonymous):

ok one sec

OpenStudy (anonymous):

d = sqrt(7-(-9)^2 + (6-(-6))^2 look okay for the first step?

jimthompson5910 (jim_thompson5910):

yes it does, keep going

OpenStudy (anonymous):

d = sqrt(x2-x1)^2 + (y2-y1)^2 d = sqrt(7-(-9)^2 + (6-(-6))^2 d = sqrt(16)^2 + (12)^2 d = sqrt(256)^2 + (144)^2 d = sqrt(65,536)+(20,736) d = sqrt(86,272) d = 293.720956 rounded: 293.7

jimthompson5910 (jim_thompson5910):

you're doing great until you hit this line d = sqrt(65,536)+(20,736)

jimthompson5910 (jim_thompson5910):

it should be this d = sqrt( 16^2 + 12^2 ) d = sqrt( 256 + 144 ) d = sqrt( 400 ) d = 20

jimthompson5910 (jim_thompson5910):

so the distance from point H to point I is 20 units

OpenStudy (anonymous):

ohhh hahaha whoops okay so from H to I is 20 and f to g is 20?

jimthompson5910 (jim_thompson5910):

correct on both

jimthompson5910 (jim_thompson5910):

you just need two more sides once you have the length of all 4 sides, you can add them up to get the perimeter

OpenStudy (anonymous):

How do I get the other two?

jimthompson5910 (jim_thompson5910):

find the distance from G to H

OpenStudy (anonymous):

Why not F to I?

jimthompson5910 (jim_thompson5910):

that's another side length we'll get to

OpenStudy (anonymous):

d = sqrt(x2-x1)^2 + (y2-y1)^2 d = sqrt(10-7)^2 + (2-6)^2 d = sqrt(3)^2 + (-4)^2 d = sqrt(9) + (16) d= sqrt(25) d = 5 The distance from G to H is 5 units.

jimthompson5910 (jim_thompson5910):

good

jimthompson5910 (jim_thompson5910):

how about from F to I

OpenStudy (anonymous):

d = sqrt(x2-x1)^2 + (y2-y1)^2 d = sqrt(-6-(-9))^2 + (-10-(-6))^2 d = sqrt(3)^2 + (-4)^2 d = sqrt(9) + (16) d = sqrt(25) d = 5 The distance from F to I is 5 units.

jimthompson5910 (jim_thompson5910):

very good

jimthompson5910 (jim_thompson5910):

now add up the 4 sides to get the perimeter

OpenStudy (anonymous):

the perimeter is 50 units

jimthompson5910 (jim_thompson5910):

perfect

OpenStudy (anonymous):

thank you!!

jimthompson5910 (jim_thompson5910):

you're welcome

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