problem ...need to be solved with real theories
\[-20=20\] \[16-36=25-45\] \[4^{2}-4\times{9 } =5^{2}-5\times{ 9 }\] \[4^{2}-2\times4\times\frac{9 }{ 2 }=5^{2}-2\times5\frac{ 9 }{ 2}\] \[4^{2}-2\times4\times\frac{9 }{ 2 }+\left( \frac{ 9 }{ 2 } \right)^{2}=5^{2}-2\times5\frac{ 9 }{ 2}+\left( \frac{ 9 }{ 2 } \right)^{2}\] \[\left( 4-\frac{ 9 }{ 2 } \right)^{2}=\left( 5-\frac{ 9}{ 2 } \right)^{2}\] \[\sqrt{\left( 4-\frac{ 9 }{ 2 } \right)^{2}}=\sqrt{\left( 5-\frac{ 9}{ 2 } \right)^{2}}\] \[4-\frac{ 9 }{ 2 }=5-\frac{ 9 }{ 2 }\] |dw:1378759825635:dw|
how can I edit ? −20=-20 m sory it meant like this both negative
what level math is this?
the high level I mean numbers on R
hmm... what definition of real number you use? Dedekind partitions maybe?
a made up confusion I am not sure the wrong step . but is 4 double of -2,2 in all condition accept geyometrical calculations when we take off the root square with absolute value ?
square root taking is like finding side of square who's diagonal is equal to the number under root sign
but still the result is not equal even if both are negative
length can never be negative
I think that's what is ment by geometrical calculations
it appears that: \[\pm (4 - \frac{ 9 }{ 2 }) = ∓(5-\frac{ 9 }{ 2 })\]
yes exactelly but why ? mean wich step is wrong and how ..
\(\sqrt{x^2}= |x|\) actually
so, if x is negative, as is the case for 4-9/2 |x| will be -x = - (4-9/2) = 1/2 for 5-9/2, x is positive so |x| =x so, 5-9/2 = 1/2
got this ?
because answer of square root can never be negative while dealing with real numbers
it's been a long time for me since i studied those. one more thing i there like a theorical proof ? texts ... and thanks seems obviously right
theoritical proof...if i find one i will attach...
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