Question

x^2+y^2+4y+2=0

Answer 1

simplify the following?

Answer 2

Show that the equation represents a circle by rewriting it in standard form, and find the center and radius of the circle.

Answer 3

Any ideas?

Answer 4

oh ok i can do that 1 sec

Answer 5

Thank you!

Answer 6

the equation for a circle is (x - h)^2 + (y - k)^2 = r^2

Answer 7

yes.

Answer 8

so we have to make the equation u gave me look like that so
x^2+y^2+4y+2=0
x^2 + (y + 2)^2 - (2)^2 = -2
x^2 + (y + 2)^2 = 2
(x + 0)^2 + (y+2)^2 = 2

Answer 9

do you understand so far?

Answer 10

yes!

Answer 11

not to rush you but i have to go soon

Answer 12

ok great :)

Answer 13

(x + 0)^2 + (y+2)^2 = 2
\[(x + 0)^2 + (y+2)^2 = (\sqrt{2})^{2}\]
therefore the coordinates of the center is (0,-2) and the radius is \[\sqrt{2}\]

Answer 14

thank you so much!!!

Answer 15

np! :)

Answer 16

you rock