Question

For f(x)=2x+1 and g(x)=x^2-7, find (f+g)(x).

Answer 1

A. x^2+2x-6
B. 2x^3-6
C. x^2+2x+8
D.2x^2-15

Answer 2

x^2 -7 + 1 + 2x , you just combine the like terms.
x^2 + 2x - 6

Answer 3

ohh that totally makes sense! thank you @shamil98 :)

Answer 4

You're welcome . :)

Answer 5

@shamil98 for f(x)=3x+1 and g(x)=x^2-6, find (f-g)(x) how would i find that? the same way like you did above?

Answer 6

Yes, but this time , you have to pay attention to (f -g ) okay? subtraction is different when the numbers are moved.
So it would be :
3x + 1
- x^2 - 6
=
-x^2 + 3x - 5

Answer 7

Remember the properties of math. :)

Answer 8

so basically instead of adding all of the numbers together, you combine them but subtract? @shamil98

Answer 9

It says (F - G) when you are adding you can add either way (f + g ) or (g+f) the result would be different if it was (G - F )

Answer 10

this is so confusing! :( lol ohhhh nevermind so i get the addition and subtracting one but what about multiplying them? like if it were f(x)=3x+1 and g(x)=x^2-6, find (f*g)(x)? @shamil98

Answer 11

would i do (3x+1)(x^2-6)?

Answer 12

It's multiplied so its distributed with the values, if you remember algebra 1 it comes handy here.
so basically its like this :
you multiply everything in one box with the other like
3x(x^2) and 3x(-6)
1(x^2) and 1(-6)
then you combine the like terms.

Answer 13

3x^3 - 18x + x^2 - 6
3x^3 +x^2 - 18x -6
is the answer.

Answer 14

oh okay, so would the answer to that be 3x^3+x^2-18x-6?

Answer 15

oh hehe just saw your answer, woohoo! I got it. thank you soo soo much i really appreciate it!! :)

Answer 16

Yeah, no problem.