Mathematics
22 Online
OpenStudy (anonymous):
tanθ (see attachment)
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
|dw:1378771355448:dw|
jimthompson5910 (jim_thompson5910):
hint:
use the unit circle and the idea that
tan(x) = sin(x)/cos(x)
OpenStudy (anonymous):
Can you do this problem with me to see if I can understand the next ones? @jim_thompson5910
jimthompson5910 (jim_thompson5910):
do you have the unit circle with you?
OpenStudy (anonymous):
Yes
Join the QuestionCove community and study together with friends!
Sign Up
jimthompson5910 (jim_thompson5910):
ok what is sin(60)
OpenStudy (anonymous):
-0.3048106211
jimthompson5910 (jim_thompson5910):
don't use a calculator
jimthompson5910 (jim_thompson5910):
use the unit circle
OpenStudy (anonymous):
Oh. \[\frac{ \sqrt{3} }{ 2 } \]
Join the QuestionCove community and study together with friends!
Sign Up
jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
it's \[\frac{ \sqrt{3} }{ 2 } \]
jimthompson5910 (jim_thompson5910):
what is cos(60)
OpenStudy (anonymous):
1/2
jimthompson5910 (jim_thompson5910):
divide sin(60) by cos(60) to get your answer
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
\[\sqrt-{3}\]
OpenStudy (anonymous):
Well - on the outside
jimthompson5910 (jim_thompson5910):
no it's positive, so the answer is actually \[\large \sqrt{3}\]
jimthompson5910 (jim_thompson5910):
hopefully you see how it's positive?
OpenStudy (anonymous):
Yes, thank you!
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
How would I find sin of 225?
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
225 is also found on the unit circle
jimthompson5910 (jim_thompson5910):
do you see it?
OpenStudy (anonymous):
Yes. What is the ratio for sin and cos I mean?
Join the QuestionCove community and study together with friends!
Sign Up
jimthompson5910 (jim_thompson5910):
don't worry about cos, just focus on sine
OpenStudy (anonymous):
I understand how to solve them, I just need the ratios now :)
OpenStudy (anonymous):
I understand all that.. Tan = sin/cos .... What is that ratio for sin and cos? I have other problems to do.
jimthompson5910 (jim_thompson5910):
there is no ratio for sine and cosine, oh you mean like
sine = opposite/hypotenuse
and
cosine = adjacent/hypotenuse
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Yes, thank you!
jimthompson5910 (jim_thompson5910):
ok glad it's clicking
OpenStudy (anonymous):
So the sin for 225 would just be - sqrt 2 over 2 right?
jimthompson5910 (jim_thompson5910):
good