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Chemistry 24 Online
OpenStudy (anonymous):

Find the density of a material, given that a 5.03 g sample occupies 3.24 mL.

OpenStudy (anonymous):

\[1.55*10^{3}\] g/L

OpenStudy (anonymous):

Could you please show the work you did to get the answer... thank you

OpenStudy (anonymous):

5.03 g / 3.24 mL => 5.03 g / .00324 L = 1552.46913... g/L You're question had 3 significant digits so I posted the answer with 3 sig. figs., thus 1.55*10^3

OpenStudy (anonymous):

Thank you very much

OpenStudy (anonymous):

You're welcome

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