Question

f(x) = \sqrt[4]{x^2 - 7 x}.

Answer 1

f(x) = \sqrt[4]{x^2 - 7 x}. I need to find the domain of this.

Answer 2

do you mean \[\sqrt[4]{x^2 - 7x}\]

Answer 3

yes

Answer 4

what level of math is this? algebra 1, 2, or calc?

Answer 5

calculus

Answer 6

the x^2-7x is what is in the square root, and the question is asking me to find the domain/

Answer 7

\[(x^2 - 7x)^.25 = 0\]

Answer 8

sorry..im having problems with the equation editor...but that is meant as 1/4

Answer 9

so the domain is 1/4?

Answer 10

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Answer 11

hold on...

Answer 12

raise both sides of the equation to the 4th power to get \[x^2 -7x = 0\] do you see it now....domain? range?

Answer 13

I don't remember how to get the domain when it is x^2

Answer 14

domain is x values

Answer 15

yes so it would be x^2=7x....so what would I do after that?

Answer 16

almost...let me write it out...

Answer 17

\[x(x-7) = 0\]

Answer 18

you have two values x = 0 and x = 7

Answer 19

yes!

Answer 20

so that means that x can't equal 0 or 7 so how would I write that out using an online application?

Answer 21

you familiar with set notation?

Answer 22

no I am not

Answer 23

\[{x \in R: x \le 0 or x \ge 7}\] means that x is in an element of the real numbers where x is less than or equal to zero OR x is greater than or equal to 7

Answer 24

is it asking for the range as well?

Answer 25

no just the domain

Answer 26

then that's it.

Answer 27

do you need further assistance?

Answer 28

what is the notation for greater than or equal, same with smaller than or equal

Answer 29

\[\ge \] is greater than or equal to....reverse the direct for less than or equal to

Answer 30

it's not working