How do I find the point slope when I only have a slope and a y-intercept?
for ex: slope= -5, y-intercept=-8
\(y\) intercept \(-8\) means the point is \((0,-8)\)
you don't need the "point - slope" formula if you know the slope is \(m\) and the \(y\) intercept is \(b\) the equation for the line is \(y=mx+b\)
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So the x intercept is 0
no
the \(x\) intercept is where the line crosses the \(x\) axis
but if i know the slope is \(2\) and the \(y\) intercept is \(5\) then i know the equation is \[y=2x+5\]
I mean if I wear to set up the point slope, it's be: (y-(-8)=-5(x-0) ?
it'd*
you could, but you wouldn't
you would go right to \(y=-5x-8\)
Oh ok, but they are asking me for a point slope
k, then you would write what you write, or \(y+8=-5x\)
oh ok
Thank you :D
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