Question

does this equation define y as a function of x:
x=y^3

Answer 1

No, you'd have to get 'y' by itself, so you'd have to take the cube root of both sides:

y = \[\sqrt[3]{x}\]

Now x is a function of y

Answer 2

oh wait

Answer 3

I read that backwards

Answer 4

Nevermind, I'm right

Answer 5

oh because my book has the answers in the back and it said yes. I just wanted an explanation

Answer 6

Really? I must not be understanding this then. I thought if you had something like

f(x) = 3x + 2, then y, written as f(x) was a function of x because y depends on what value you give for x