Express the volume of a cone, V, as a function of its radius, r, if the radius is 1/3 of the height. I tried (1/9) *pi * r^2 but it's wrong.
Cone Volume = (π • r² • h) / 3 ((3 • Cone volume) / π) =r² • h If you want to calculate the volume of a cone when h/3 = r then let h = 6 and r = 2 Volume = 25.133 I think you want to calculate the relation between volume of a cone and radius but it seems the volume is connected both to the radius and the height.
It's supposed to be r^3, not r^2.
blockcolder Visit this link http://math.about.com/od/formulas/ss/surfaceareavol_2.htm or here http://www.math.com/school/subject3/lessons/S3U4L4DP.html or here http://wiki.answers.com/Q/What_is_the_formula_for_volume_of_a_cone and you will see those sites state that the volume of a cone is: (π • r² • h) / 3
Yeah, and it was stated that the radius is 1/3 of height; i.e. r=h/3 or equivalently, h=3r. Thus, the formula for volume becomes \(\frac{\pi r^2(3r)}{3}=\pi r^3\). I should have clarified that I was referring to OP's formula, not yours. My bad.
Okay blockcolder. Yeah and I think I was a little too "quick on the draw" in my reply. And why hasn't mango213 shown up yet?
He's probably offline right now.
Anyway, I'm glad we got our disagreement all cleared up.
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