Factor the expression completely. x^4-y^4
Its the difference of two squares. What would be your factor then?
Remember when multiplying we add exponents.
(x^2-y^2) (x^2+y^2) but then i dont know what you do after that
That is the final answer. :)
Oh wait
and you still have a difference of 2 sq
to factor
(x^2-y^2) , is also a difference of two squares, so you should factor it also
(x^2+y^2), is final and has no factors
idk whats wrong but it still says I have the wrong answer :(
Did you factor them correctly?
\[(x+y)(x-y)(x^2+y^2)\]
Stop giving away answers @John_ES
Ok, I think this was finished and no one was replying them. Sorry, I don't see that the response was recent ;).
OMG!!! Thank you so much @John_ES I was writing it (x^2+y^2)(x+y)(x-y) and it would not work. But your answer did!!
Please note that, since its multiplication we can interchange the position of our binomials.
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