if the number of subsets with 4 elements of a set A is equal to the number of subsets with 5 elements of the set, then the number of subsets with 3 elements of this set is ?
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Suppose: \[ \|A\| = n \]
if the number of subsets with 4 elements of a set A is equal to the number of subsets with 5 elements of the set\[ \binom{n}{4}=\binom{n}{5} \] then the number of subsets with 3 elements of this set is\[ \binom{n}{3}=x \]
Solve for \(n\), then solve for \(x\).
\[ \binom{n}{k}\iff ^nC_k\iff (n\text{ choose }k) \]
\[ \binom nk=\frac{n!}{k!(n-k)!} \]
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