Question

Given the equation radical 8x+1 = 5, solve for x and identify if it is an extraneous solution.
a. x = 1/4 , solution is not extraneous

b. x =1/4 , solution is extraneous

c. x = 3, solution is not extraneous

d. x = 3, solution is extraneous

Answer 1

you mean \[\sqrt{8x +1}\] = 5 ?

Answer 2

Is it the question ?
\[sqrt{8x+1}\]=5
Please answer and get answer :)

Answer 3

@yamyam70 yes

Answer 4

hello,
if a linear equation has a radical , square both sides :)

Answer 5

so it would be 64x+1=25

Answer 6

\[(\sqrt{8x + 1} )^2 = (5)^2\]

Answer 7

nope, by squaring both sides, take notice of the left hand side, we remove the radical.

Answer 8

\[\sqrt{8x + 1 } \times \sqrt{8x +1} = 8x +1 \]

Answer 9

so the left side would stay 8x+1

Answer 10

aha!

Answer 11

so please continue, 8x + 1 = (5)^2 :)

Answer 12

x=3?

Answer 13

How did you get that answer? :)

Answer 14

subtract 1 from each side then divide by 8.

Answer 15

what does extraneous solution mean?

Answer 16

Correct! How would you tell if it is extraneous or not?

Answer 17

idk what that means.

Answer 18

We check the equation, by substituting the value of x. :)

Answer 19

i got 5=5

Answer 20

if you check it and the results of the left hand side is equal to the right hand side it is not extraneous :) if it does not equal , it is extraneous :)

Answer 21

oh ok thankyou!

Answer 22

Welcome to open study! please read the code of conduct if you have time :)

Answer 23

http://openstudy.com/code-of-conduct

Answer 24

you're welcome :)

Answer 25

another question!

Answer 26

sure :)

Answer 27

Solve for x, given the equation \[\sqrt{x-5}+7=11\]

x = 21, solution is extraneous

x = 21, solution is not extraneous

x = 81, solution is extraneous

x = 81, solution is not extraneous

Answer 28

I see
then same procedure, square both sides :)

Answer 29

x-5+49=121

Answer 30

oh wait, 7 isn't involved

Answer 31

one moment please

Answer 32

ok

Answer 33

are you sure about the given choices?

Answer 34

yes i got 77 but that answer was not there

Answer 35

I see, we got same, I'm trying a different approach, one moment

Answer 36

ok

Answer 37

okay here goes,

Answer 38

\[\sqrt{x-5} +7 =11\]

Answer 39

we tranfer 7 to the right hand side :)

Answer 40

what would we have?

Answer 41

\[\sqrt{x-5}=18\]

Answer 42

and then do we square both sides?

Answer 43

wrong :) , when we tranfer 7 , we change the signs right? :)

Answer 44

yes the right side is supposed to be 4

Answer 45

correct :) then we square both sides, the equation should look like \[\sqrt{x-5} = 4 \]

Answer 46

i got x= 17

Answer 47

wrong :)

\[(\sqrt{x-5?})^2 = (4)\]

Answer 48

(x−5?−−−−−√)2=(4)^2

Answer 49

do i foil them?

Answer 50

wait nevermind that

Answer 51

\[(\sqrt{x-5})^2=(4)^2\]

Answer 52

^^^^^^ thats the correct one

Answer 53

so how to i solve for that?

Answer 54

remember when we square , \[\sqrt{x-5}\] it will give us x-5 :)

Answer 55

\[(\sqrt{x-5}) (\sqrt{x-5}) = x-5\]

Answer 56

x=21

Answer 57

correct :) , so check if it is extraneous or not :)

Answer 58

it is not

Answer 59

Correct :)

Answer 60

Given the equation \[\sqrt[-4]{x-3}=12\], solve for x and identify if it is an extraneous solution.

x = 0, solution is not extraneous

x = 0, solution is extraneous

x = 12, solution is not extraneous

x = 12, solution is extraneous

Answer 61

is that -4 ?

Answer 62

yes

Answer 63

would it be this \[x-3\frac{ 1 }{ -4}=12\]

Answer 64

hmm, I'm not quite sure about the rule here.

Answer 65

I would suggest too start another session. :)

Answer 66

I'm sorry , I can't help you with this one :)

Answer 67

ok thanks for the help

Answer 68

Bye :)

Answer 69

Don't forget to close the question :)

Answer 70

how do i do that?

Answer 71

On the left side, there is a timer, "bump in" beside it click close. :)