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Precalculus
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use the given zero to find the remaining zeros of the function. f(x) = x^3-2x^2-11x+52; zero: -4
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so, we know that a zero/solution/root is -4, or that is x = -4 meaning (x+4) x = -4 => (x+4) = 0 if you divide the polynomial by any of its roots, you'd get a zero as remainder so your quotient, will be the one you'd need to factor in order to get the other roots so what would you get for \(\bf \cfrac{ x^3-2x^2-11x+52}{x+4}\)
im not quite sure how i could divide that out
use long division
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