Question

A small fish is dropped by a pelican that is rising steadily at 0.50 m/s. How far below the pelican is the fish after 2.5 s?
A) 61 m
B) 29.3 m
C) 30.6 m
D) 1.1 m
Can you tell me the formula in order to find this?

Answer 1

To find the distance while it rises:
d=vt

Answer 2

So, how would you find the velocity (I assume that's what "v" stands for)

Answer 3

1) Calculate how far the pelican rises in 2.5s:\[(0.50 m/s)(2.5s)=1.25m\]2) Calculate how far the fish drops in 2.5s given it's initial upward velocity of 0.50m/s:\[d=v_0t+\frac{1}{2}gt^2=(0.50m/s)(2.5s)+\frac{1}{2}(-9.8m/s^2)(2.5s)^2=-29.375m\]
3) Add the distances:\[|-29.375m|+1.25m=30.625m\]

Answer 4

thank you SO much, that really helped. Thanks for explaining it to, instead of just giving the answer :)

Answer 5

np :)