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The position of an object as a function of time is given x=bt^2 -ct , where b=2.0 m/s^2 and c=6.7 m/s, and x and t are in SI units. What is the instantaneous velocity of the object when t=2.2?
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So x=2t^2-6.7t. When t=2.2, x=2(2.2)^2-6.7*2.2 x=-5.06...
Oh wait
Sorry
You need the derivative
x=2t^2-6.7t. The derivative is 4t-6.7 So the velocity is 2.1 m/s
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This is Calc right?
this right answer
Calc-Based Physic.)
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