Question

Sketch the graph of a single function f that has the
following properties. NOTE: There are many correct
answers.

•f(-2)=3

•lim f(x) does not exist
x--> -2

•lim f(x)=-2
x--> 2+

•f(4)=5

•f(x)=2
x-->4

How would I do this? Is there a way anyone can show me? o.O We never did graphs in class yet. Is there a link or a process of how to do this that anyone can show me?

Answer 1

make a function that jumps at \((-2,3)\)

Answer 2

ok i screwed that all up, i should learn to read

Answer 3

\(f(-2)=3\) means the point \((-2,3)\) is on the graph
\[\lim_{x\to -2}f(x)\] does not exist means there is some sort of discontinuity there, a jump will work nicely

Answer 4

is number 3 this
\[\lim_{x\to 2^+}f(x)=-2\] or this \[\lim_{x\to -2^+}f(x)=-2\]

Answer 5

it will make a difference, and i am thinking it might be the second, even though you wrote the first

Answer 6

It was supposed to be the first one. Not the second one

Answer 7

ok

Answer 8

lets take care of the first two first

Answer 9

circle closed at \((-2,3)\) means \(f(-2)=3\) and the jump means the limit at \(-2\) does not exist

Answer 10

more or less clear?

Answer 11

What do you mean by "the limit at −2 does not exist" :O