4cos(theta)-theta, given point (0,0)

Question

psymon · Answer

Tangent line or something else?

anonymous · Answer

find the slope with given point, f(theta)= 4sin(theta)-theta i know the derivative would be -4cos(theta)- something, so is that something one or zero, basically the derivative of theta?

anonymous · Answer

*no positive4cos(theta)

psymon · Answer

Derivative would be -4sin(theta) and yes, derivative of theta is just 0. Its just as if it were an x.

psymon · Answer

Oh, sorry, 1 then x_x

psymon · Answer

-4sin(theta) -1

Brain being dumb.

anonymous · Answer

why 1 and not zero that is  where im somewhat confused

psymon · Answer

Well, theta is just a variable. if it weren't a variable, we'd have nothing to plug 0 into when we try to find the slope. So we have to act like this is actually

4cos(x) - x

Inw hich case the derivative of x is just 1 and 4cosx becomes -4sinx

anonymous · Answer

oh okay thanks because i knew it wasnt a constant

psymon · Answer

yeah, my brain wentdumb on me. SO yeah, -4sinx - x. So now just plug in the x-coordinate of your point.

anonymous · Answer

okay thanks again

psymon · Answer

mhm :3