Question

Question 15 (Multiple Choice Worth 5 points)

[9.05] Solve 3x2 + 5x + 7 = 0. Round solutions to the nearest hundredth.

No real solutions

x ≈ −6.34 and x ≈ 1.34

x ≈ −0.45 and x ≈ 2.11

x ≈ −2.11 and x ≈ 0.45

Answer 1

hi felicia123...at it again hu? lol! Okay, so u can use the pathagoriean therom again to find the x intercepts...remember its\[(-b + or - \sqrt{b^2-4*a*c})/2a\]

Answer 2

\[x1= (b + \sqrt{b^2-4*a*c})/2a\]
and
\[x2= (b - \sqrt{b^2-4*a*c})/2a\]

Answer 3

remember that a quadratic has the form a^2+b+c=0

Answer 4

can you just tell me how to do this in the cal

Answer 5

okay a=3, b=5 and c=7.... :)

Answer 6

Is it A

Answer 7

idk

Answer 8

i think its a because of the 0

Answer 9

\[x1= (5 + \sqrt{5^2-4*3*7})/2a\]

Answer 10

it be 3x ^2-5x+7 =0

Answer 11

so b= -5

Answer 12

put -5 for b in the formula

Answer 13

-5