Find the equation of the line with slope -3 containing the point (-1, 5) in both point-slope form and slope-intercept form

Question

anonymous · Answer

Well you know point-slope to be:
$$y-y _{1}=m(x-x _{1})$$And Slope intercept form:
$$y=mx+b$$So for point slope you can plug in m as -3 and (-1,5) as $$(x _{1},y _{1})$$
Then solve, for slope intercept form, you plug in (-1, 5) and m=-3 and solve for b and then rewrite it as y=mx+b. Hope it helps :)

anonymous · Answer

when solving for the slope intercept i know the formula is y=mx+b, but is b 5 or would it be 2 from when you solve for the point slope...the point slope i got is y=-3x+2 so does b =2. in this question would the point slope be y=-3x+5 or y=-3x+2?

anonymous · Answer

Well the coordinate y (5) is not b, remember b is the y-intercept. So,
y=mx+b
5=(-3)(-1)+b      solve for b here
5=3 + b
2= b 
Thus, y=-3x+2 just like the point-slope.

anonymous · Answer

ok, great thank you so much

anonymous · Answer

Yep, Good Luck :)