A baseball is thrown straight up in the air at with an initial velocity of 60 feet per second (roughly 40 mph). The height of the baseball as a function of time is then given by s(t) = -16 t^2 + 60t. Determine the instantaneous velocity of the ball after 1, 2 and 3 seconds.

Question

anonymous · Answer

Find the derivative.  Then plug in $1$, $2$, and $3$.

anonymous · Answer

Take the derivative of the equation so: -16(2)=-32t+(60)(1) by using the power rule. so s'(t) = -32t+60. Then plug 1, 2, and 3 into the equation to get the instantaneous velocity for the ball after each second. So I got 28 for 1 second, -4 for 2 seconds, and -36 for 3 seconds.

anonymous · Answer

thank you that really helps.