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Mathematics 10 Online
OpenStudy (anonymous):

Find the value of tan θ for the angle shown.

OpenStudy (anonymous):

OpenStudy (anonymous):

\[ \tan \theta =\frac{\sin \theta}{\cos\theta} \]

hartnn (hartnn):

tan ratio in cartesian is defined by just y/x

OpenStudy (anonymous):

\[ (\cos\theta,\sin\theta) = (\sqrt{33},-4) \]

hartnn (hartnn):

tan theta = y co-ordinate/ x co-ordinate

OpenStudy (anonymous):

So it would be sqrt 33/4 all negative?

OpenStudy (anonymous):

\(\color{blue}{\text{Originally Posted by}}\) @wio \[ \tan \theta =\frac{\sin \theta}{\cos\theta} \] \(\color{blue}{\text{End of Quote}}\) \(\color{blue}{\text{Originally Posted by}}\) @wio \[ (\cos\theta,\sin\theta) = (\sqrt{33},-4) \] \(\color{blue}{\text{End of Quote}}\) \[ \tan\theta = \frac{-4}{\sqrt{33}} \]

hartnn (hartnn):

no...the numerator is actually y co-ordinate

hartnn (hartnn):

you know what a y co-ordinate is ?

OpenStudy (anonymous):

The answer above is not one of my options. These are my options. tan θ = - sqrt33/4 tan θ = - 4sqrt33/33 tan θ = - 4/7 tan θ = - sqrt33/7

hartnn (hartnn):

you will have to rationalize the denominator, know how to ?

OpenStudy (anonymous):

I do not, this is just a practice problem so im trying to see how to get the answer so i can try others on my own.

hartnn (hartnn):

ok, sqrt 33 is an irrational number to rationalize it, multiply it by another sqrt 33

OpenStudy (anonymous):

\[ \frac{-4}{\sqrt{33}} = \frac{-4}{\sqrt{33}} \times \frac{\sqrt{33}}{\sqrt{33}}= \frac{-4\sqrt{33}}{33} \]

hartnn (hartnn):

but when you multiply sqrt 33 in the doniminator, you will have to multiply it in numerator too

hartnn (hartnn):

like what @wio did

OpenStudy (anonymous):

Ohhhhhhhh thats why -4/sqrt33 wasnt one of my answers! Thanks i got it now!

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