Find the value of tan θ for the angle shown.
\[ \tan \theta =\frac{\sin \theta}{\cos\theta} \]
tan ratio in cartesian is defined by just y/x
\[ (\cos\theta,\sin\theta) = (\sqrt{33},-4) \]
tan theta = y co-ordinate/ x co-ordinate
So it would be sqrt 33/4 all negative?
\(\color{blue}{\text{Originally Posted by}}\) @wio \[ \tan \theta =\frac{\sin \theta}{\cos\theta} \] \(\color{blue}{\text{End of Quote}}\) \(\color{blue}{\text{Originally Posted by}}\) @wio \[ (\cos\theta,\sin\theta) = (\sqrt{33},-4) \] \(\color{blue}{\text{End of Quote}}\) \[ \tan\theta = \frac{-4}{\sqrt{33}} \]
no...the numerator is actually y co-ordinate
you know what a y co-ordinate is ?
The answer above is not one of my options. These are my options. tan θ = - sqrt33/4 tan θ = - 4sqrt33/33 tan θ = - 4/7 tan θ = - sqrt33/7
you will have to rationalize the denominator, know how to ?
I do not, this is just a practice problem so im trying to see how to get the answer so i can try others on my own.
ok, sqrt 33 is an irrational number to rationalize it, multiply it by another sqrt 33
\[ \frac{-4}{\sqrt{33}} = \frac{-4}{\sqrt{33}} \times \frac{\sqrt{33}}{\sqrt{33}}= \frac{-4\sqrt{33}}{33} \]
but when you multiply sqrt 33 in the doniminator, you will have to multiply it in numerator too
like what @wio did
Ohhhhhhhh thats why -4/sqrt33 wasnt one of my answers! Thanks i got it now!
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