Question

There are 10 blue balls, 7 red balls, 14 green balls, 12 yellow balls, 9 black balls and 1 purple ball inside a bag. What is the minimum number of balls that must be drawn to ensure that at least one triplet of balls (three balls of same colour) is definitely present among the balls chosen?

Answer 1

there's a total of 53 balls. 53/3? I don't know if that's the step but the result is 17 so a 17/53 chance?

Answer 2

i didnt get that answer

Answer 3

Well, considering I probably did another method than what you did, tell me what answer you got and how

Answer 4

28.345 something

Answer 5

total-23726,atleast three balls of same colour right

Answer 6

what the hell? why would you do 3-23726? where the hell did you get 23726 from??

Answer 7

please give respect while answering

Answer 8

I'm not disrespecting you, I asked a question

Answer 9

53C3-23726

Answer 10

53*52*51/3*2

Answer 11

53C3? Huh?

Answer 12

yes combinations

Answer 13

You have 10 + 7 +14 + 12 + 9 + 1 = 53
I don't know where you're getting this "combinations" from. Although, you seem to know how to work your own problem out.

Answer 14

out of 53 we are taking three balls

Answer 15

plse help me

Answer 16

There are balls of six different colours - blue, red, green, yellow, black and purple.

There is a chance that the first three balls itself form a triplet. However, with three balls, one cannot ensure that a triplet is definitely formed.

In the worst case, assume that the first six balls drawn are of different colours. Now, there are no purple balls left. So, the balls left are of five different colours.

Again, if the next five balls that are drawn are of different colours, we definitely have two balls each of five colours and the solitary purple ball (when 11 balls have been drawn).

All the other colours originally have more than two balls.

So, the 12th ball that is drawn is definitely the third ball of any colour.

Thus, a triplet can be ensured after at least 12 balls are drawn.

Answer 17

i cant understand please tell me

Answer 18

k i have understood @jibirajeev

Answer 19

first time we drawn 6 balls and then 5...so its 11... and in the next draw you need only onew ball to get a triplet .. so altogether...12

Answer 20

i am so weak in quants to understand this kind of problems .i am daily preparing maths.still i didnt get this type of questions

Answer 21

what to do

Answer 22

Practice....practice...