While simplifying some math work, Peter wrote on his paper that x3 • x3 • x3 • x3 equaled x3+ 3 + 3 +3 . Did Peter simplify his work correctly and completely to a final answer? Would Peter’s work be the same if he were to simplify x3 + x3 + x3 + x3?

Question

anonymous · Answer

@E.ali

anonymous · Answer

no peters simplification is wrong

anonymous · Answer

It is?

anonymous · Answer

a^b*a^c=a^(b+c) this is not equal to a^b+a^c

anonymous · Answer

peters simplification is right in the first case but the latter one is wrong i meant

anonymous · Answer

but it looks like the simplification in question is$$\large x^3\cdot x^3\cdot x^3\cdot x^3=x^{3+3+3+3}$$

anonymous · Answer

ammm...
But I think is ... because computers have another langouege :)
do u know any thinks about radix ?

anonymous · Answer

the above simplification is right

anonymous · Answer

radix is nothing different from base of a number system it  informs about the structural design of a number system and conveys the number of digits used in that system

yttrium · Answer

Yes is the answer for the first question since it will arrive at x^12. But in the Second (addition) it will absolutely not applicable. Because that adding of exponents is only applicable in multiplication of same base. (You see they are all the same x that is why you can add all of the exponent) But in addition, if you have same term, what you can only do is to add the coefficient. Since they are all x^3 you can add them up. Arriving at 4x3. Do you understand me? Sorry for very long answer

anonymous · Answer

dont be sorry for a long answer if it helps :)

anonymous · Answer

but how does x3 • x3 • x3 • x3 equaled x3+ 3 + 3 +3 and x3 + x3 + x3 + x3= 4x3

anonymous · Answer

x3 + x3 + x3 + x3= 4x3 makes sense but im confused about the x3 • x3 • x3 • x3 equaling x3+ 3 + 3 +3

anonymous · Answer

They are all exponents btw

yttrium · Answer

It will arrive at \[x ^{3+3+3+3}  = x ^{12}]

anonymous · Answer

Thank you

yttrium · Answer

No problem @bbbbbbbbbbbbbbbbbb

anonymous · Answer

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