Question

Simplify each of the following expressions as much as possible..

Answer 1

\[\frac{ (i+2)! }{ (i-1)! }\]

Answer 2

Not sure how to start these..explain?

Answer 3

they dont like i in the denominator multiply by complex conjugate :)

Answer 4

well madam,(i+2)! = (i+2)(i+1)(i)...
and (i-1)! = (i-1)(i-2)...
and do you have any idea to solve it? :)

Answer 5

need help?

Answer 6

Does something cancel out along the way?

Answer 7

no :)

Answer 8

I'm all confused! How do you know what to do?

Answer 9

ok,i will tell you:
notice this examples,and try it yourself...
\[\frac{ (5+2)(5+1)(5)(5-1)(5-2)(5-3)(5-4) }{ (5-1)(5-2)(5-3)(5-4) }\]

Answer 10

and can you solve it?

Answer 11

I just don't understand what I'm trying to do. I can see that you're using the same pattern and that after a certain point you're getting the same numbers

Answer 12

you should solve it like this:

Answer 13

so the answer is 7x6x5 = 210

Answer 14

So it does kind of like cancel out? Would my answer just be i+2?

Answer 15

no the answer won't be i+2 , see:
\[\frac{ (i+2)(i+1)(i)(i-1)... }{ (i-1)(i-2)... }\]

Answer 16

i-1? I don't get how it'll stop at i, after you cross out i-1.

Answer 17

I can't wrap my mind around it I'm sorry :(

Answer 18

we have i-1 , i-2 , i-3 , ...so we should cross out i-1 , i-2 , i -3 , ... and WE CAN'T CROSS OUT i+2 , i+1 , i so the answer is i+2 , i+1 , i

Answer 19

But that's it??????

Answer 20

what?

Answer 21

Okay that makes sense I think. Thank you

Answer 22

welcome madam :)