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Mathematics 17 Online
OpenStudy (anonymous):

Find part "b". https://media.glynlyon.com/g_geo_2013/5/01.gif Math please help

OpenStudy (anonymous):

i says the answer is something like this blank=4blank/blank

OpenStudy (anonymous):

\[\frac{ x }{ 15 }=\sin 30=\frac{ 1 }{ 2 },x=\frac{ 15 }{ 2 },\]

OpenStudy (anonymous):

im confused >.<

OpenStudy (anonymous):

how?

OpenStudy (anonymous):

b=4blank/blank but there was no 4

OpenStudy (anonymous):

|dw:1378916482495:dw|

OpenStudy (anonymous):

this https://media.glynlyon.com/g_geo_2013/5/01.gif

OpenStudy (anonymous):

wait i have not completed the question. first find x as i have found. then y from smaller two triangles then equate y to find b

OpenStudy (anonymous):

you may also find z by pythagoras theorem sides are 15 and 15/2

OpenStudy (anonymous):

find z, i will see your work.

OpenStudy (anonymous):

15^2+15/2^2 = 1125/4 or 281.25

OpenStudy (anonymous):

right?

OpenStudy (anonymous):

\[z=\sqrt{\left( 15 \right)^{2}-\left( \frac{ 15 }{ 2 } \right)^{2}}=15\sqrt{1-\frac{ 1 }{4 }}=\frac{ 15\sqrt{3} }{2}\]

OpenStudy (anonymous):

\[\frac{ b }{z }=\cos 30=\frac{ 1 }{ 2 },b=\frac{ z }{ 2 }=\frac{ 15\sqrt{3} }{4 }\]

OpenStudy (anonymous):

|dw:1378917463146:dw|

OpenStudy (anonymous):

correction write 15/2 in place of 4 in the diagram.

OpenStudy (anonymous):

you have to find x first. if you have any doubt you can ask me.

OpenStudy (anonymous):

i cant replace the 4 tho its fill in the blank on my online class

OpenStudy (anonymous):

one more correction \[ \cos 30=\frac{ \sqrt{3} }{2 }\]

OpenStudy (anonymous):

\[b=\frac{ 15\sqrt{3} }{ 2 }*\frac{ \sqrt{3} }{ 2 }=\frac{ 45 }{4 }\]

OpenStudy (anonymous):

:D

OpenStudy (anonymous):

you can solve this question by many ways e.g., similarity of triangles.

OpenStudy (anonymous):

thank you so much !

OpenStudy (anonymous):

yw

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