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OpenStudy (anonymous):
Can you solve this
OpenStudy (anonymous):
@phi
OpenStudy (phi):
when you multiply numbers with the same base, you add their exponents.
OpenStudy (anonymous):
when it says \[gx\] does that mean both g and x have exponents of 4 or just x
OpenStudy (anonymous):
\[gx ^{4}\]
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OpenStudy (anonymous):
xg^2/11
OpenStudy (anonymous):
?
OpenStudy (anonymous):
So first you need to know your orders of operations. You are given that 11sqrt(x^6gx^4x^2) which is the same as (x^6gx^4gx^2)^(1/11). Now do the parenthesis first (x^6gx^4gx^2)= (x^6gx^6). Remember root times a root is addition. So you would get (x^6gx^6)^(1/11). Overall the answer should be [(x^(6/11)gx^(6/11)]
OpenStudy (anonymous):
how is x^6
OpenStudy (anonymous):
wouldnt it be x^5
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OpenStudy (anonymous):
x^5 my bad didnt zoom into the problem
OpenStudy (anonymous):
everything is the same just change it to x^5
OpenStudy (anonymous):
oh, and can i solve that any further?
OpenStudy (anonymous):
You could but it would look like this x^(5/11)*(1*gx^(1/11)). But it is better to keep it as it is from the first answer.
OpenStudy (anonymous):
\[\frac{ 1 }{ x ^{-1 }}\]
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