Question

(2x^3 y^-1/4)^2 (8y^-3/2)-1/3

Answer 1

I'm sorry but what is the question?

Answer 2

In parentheses 2x with the exponent 3, y with the exponent negative 1/4, close parentheses then all of that in the parentheses with the exponent 2. Then in the other parentheses 8y with the exponent -3/2, close parentheses with the exponent -1/3

Answer 3

give answer choices

Answer 4

There aren't any answer choices.

Answer 5

wow okay hold on

Answer 6

Hey thank you guys for being so responsive and to Wolfe8 my question was find allvalues of x in the interval [0,2pi] that satisfy the equation. 2cosx-1=0. thank you again for you guys.

Answer 7

I'm very sorry but I still don't understand what the question wants. It doesn't have any equality. Does it want you to just simplify it?

Answer 8

See thats just my problem I dont quite undertand what the problem is asking. All my text book says is find all values of x in the interval [0,2pi] that satisfy the equation. and the equation is 2cosx-1=0. I know this problem is a real tricky one!

Answer 9

Josephine is that the same question as the one posted here?

Answer 10

Yesindeed it is.

Answer 11

In that case, do as you would for any equality. Add both sides with 1 so you are left with:
2cosx = 1

Then divide both sides with 2:
cosx = 1/2

Now I'm not sure if you have the basic values memorized but you will need a calculator for this. To obtain x on the left side, you will have to use an anti-cos(not sure the name). It is denoted as cos^{-1}
Do that to both sides and obtain x = ?

Because the question says all values, you will (usually) need more than one answer to that. The calculator will give you one value. Sketch that angle in the cartesian plane. Can you do it from here? The second part needs quite an explanation.

Answer 12

Thank you so much, Wolfe8! this is very comprehensive. However, their is one problem; I'm in a calculus 112 class and my professor doesn't allow the use of calculators so that intensifies the difficulty of the problem.

Answer 13

Then you'l have to memorize some common cos, sin and tan values. I have 2 triangles you can draw anytime you need them and they will give you the values for those common angles. I will post it here when I have it.

Answer 14

Okay thanks so much and yes I must memorize them! I took pre calc in high school and all I remember/ was tought is soh cah toa!!

Answer 15

http://www.maths.surrey.ac.uk/hosted-sites/R.Knott/Fibonacci/simpleTrig.html

That page should be helpful. Somewhere down the middle you will find 2 triangles that will give values for the cos, tan and sin, of 30, 45 and 60 degrees. There are more too. Check it out.

Answer 16

Wolfe8 you have been a great help! again I thank you as well as the other commentators on this problem. We'll I'm off to check out that web link.