Question

Help(:

Answer 1

\[s _{26} for -31+(-27)+(-23)+(-19)+... enter the s u m\]

Answer 2

@austinL

Answer 3

We are looking for,
\(\large{S_{26}}\)
And our initial term is \(a_{0}=-31\).
So can we reasonably say that our problem is,
\(\large{\sum\limits_{k=1}^{26}a_0+4,~a_0=-31}\)
I believe this is the correct setup.

Answer 4

ok

Answer 5

is it like the last one where you add?

Answer 6

After you have the initial value(a0) and d(change), use the formula for sum.

Answer 7

Do you have a scientific calculator?

Answer 8

no):

Answer 9

http://speedcrunch.org/en_US/download.html <----

Answer 10

You can use this formula, which is something you should memorize.

Answer 11

\(a_0+4\)
\(a_0=-31\)
\(a_0+4=a_1=-27\)
\(a_1+4=a_2=...\)
And it continues on.
I believe I made an error in the set up, but this is basically how you do it.

Answer 12

This page should help: http://www.mathsisfun.com/algebra/sequences-sums-arithmetic.html

Answer 13

thank you(: