Write an inequality for the graph.
first off, notice the vertex, and also that's an absolute value function graph what would be your vertex?
Could you explain more? I don't understand
Hello?
Please can somebody help?
@jdoe0001 ? @oscar1997flores
woops, sorry, was a bit .. .caught up
notice the coordinates for the vertex , what can you see as the vertex coordinates?
I don't understand that, can you explain what that is?
the vertex.... you know is an absolute value expression, right? based on the graph, the graph of absolute value expressions look like http://education-portal.com/cimages/multimages/16/transformations.jpg
Alright, I understand I see that the vertex is hitting (5,1) right?
right, the vertex is (5, 1) the lines are SOLID, that means is going to be either \(\bf \le \ or \ \ge\ \) when is > or < is a DASHED LINE the absolute parent expression will be |x| simple enough it's SHIFTED HORIZONTALLY by 5 units, that means | x - 5 | it's SHIFTED VERTICALLY by 1 unit UP, that means | x -5 | + 1 so that's our left side... so our right side will be "y" so \(\bf \large | x - 5 | +1 \quad \square ? \quad y \) what goes between it? we dunno but we have a shaded area, which is the area that's TRUE for the inequality so pick a point in the shaded area, or TRUE for the inequality, that we can test :)
shifted horizontally by 5units to the right that is, which is |x -5 |, anyhow, pick a point in the TRUE or shaded are
2?
(2, ? )
Lets say 5?
ok, (2, 5) is in the TRUE or shaded area, so our inequality must yield true so let's test it x = 2, y = 5 \(\bf | x - 5 | +1 \quad \square ? \quad y \\ \quad \\ | (2) - 5 | +1 \quad \square ? \quad (5) \implies |-3| +1 \quad \square ? \quad (5)\\\quad\\ \implies -3 +1 \quad \square ? \quad (5) \implies -2 \quad \square ? \quad 5\\ \textit{well, -2 is clearly less than 5, recall we have to use} \le \ or \ \ge\\ -2 \quad \square ? \quad 5 \implies -2 \le 5\\ \textit{so our sign is } \le\\ | x - 5 | +1 \quad \square ? \quad y \implies \color{blue}{| x - 5 | +1 \quad \le \quad y }\)
Ah so |x−5|+1≤y would be the answer?
hhhmm one sec.... I have an error :(
|-3| = 3
ok
\(\bf | x - 5 | +1 \quad \square ? \quad y \\ \quad \\ | (2) - 5 | +1 \quad \square ? \quad (5) \implies |-3| +1 \quad \square ? \quad (5)\\ \quad \\ \implies 3 +1 \quad \square ? \quad (5) \implies 4 \quad \square ? \quad 5\\ \textit{well, 4 is clearly less than 5, recall we have to use} \le \ or \ \ge\\ 4 \quad \square ? \quad 5 \implies 4 \le 5\\ \textit{so our sign is } \le\\ | x - 5 | +1 \quad \square ? \quad y \implies \color{blue}{| x - 5 | +1 \quad \le \quad y} \) still less than 5 anyhow
So that's the answer?
yeap, that's the inequality
Thank you!
yw
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