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Mathematics 24 Online
OpenStudy (anonymous):

Write an inequality for the graph.

OpenStudy (anonymous):

OpenStudy (jdoe0001):

first off, notice the vertex, and also that's an absolute value function graph what would be your vertex?

OpenStudy (anonymous):

Could you explain more? I don't understand

OpenStudy (anonymous):

Hello?

OpenStudy (anonymous):

Please can somebody help?

OpenStudy (anonymous):

@jdoe0001 ? @oscar1997flores

OpenStudy (jdoe0001):

woops, sorry, was a bit .. .caught up

OpenStudy (jdoe0001):

notice the coordinates for the vertex , what can you see as the vertex coordinates?

OpenStudy (anonymous):

I don't understand that, can you explain what that is?

OpenStudy (jdoe0001):

the vertex.... you know is an absolute value expression, right? based on the graph, the graph of absolute value expressions look like http://education-portal.com/cimages/multimages/16/transformations.jpg

OpenStudy (anonymous):

Alright, I understand I see that the vertex is hitting (5,1) right?

OpenStudy (jdoe0001):

right, the vertex is (5, 1) the lines are SOLID, that means is going to be either \(\bf \le \ or \ \ge\ \) when is > or < is a DASHED LINE the absolute parent expression will be |x| simple enough it's SHIFTED HORIZONTALLY by 5 units, that means | x - 5 | it's SHIFTED VERTICALLY by 1 unit UP, that means | x -5 | + 1 so that's our left side... so our right side will be "y" so \(\bf \large | x - 5 | +1 \quad \square ? \quad y \) what goes between it? we dunno but we have a shaded area, which is the area that's TRUE for the inequality so pick a point in the shaded area, or TRUE for the inequality, that we can test :)

OpenStudy (jdoe0001):

shifted horizontally by 5units to the right that is, which is |x -5 |, anyhow, pick a point in the TRUE or shaded are

OpenStudy (anonymous):

2?

OpenStudy (jdoe0001):

(2, ? )

OpenStudy (anonymous):

Lets say 5?

OpenStudy (jdoe0001):

ok, (2, 5) is in the TRUE or shaded area, so our inequality must yield true so let's test it x = 2, y = 5 \(\bf | x - 5 | +1 \quad \square ? \quad y \\ \quad \\ | (2) - 5 | +1 \quad \square ? \quad (5) \implies |-3| +1 \quad \square ? \quad (5)\\\quad\\ \implies -3 +1 \quad \square ? \quad (5) \implies -2 \quad \square ? \quad 5\\ \textit{well, -2 is clearly less than 5, recall we have to use} \le \ or \ \ge\\ -2 \quad \square ? \quad 5 \implies -2 \le 5\\ \textit{so our sign is } \le\\ | x - 5 | +1 \quad \square ? \quad y \implies \color{blue}{| x - 5 | +1 \quad \le \quad y }\)

OpenStudy (anonymous):

Ah so |x−5|+1≤y would be the answer?

OpenStudy (jdoe0001):

hhhmm one sec.... I have an error :(

OpenStudy (jdoe0001):

|-3| = 3

OpenStudy (anonymous):

ok

OpenStudy (jdoe0001):

\(\bf | x - 5 | +1 \quad \square ? \quad y \\ \quad \\ | (2) - 5 | +1 \quad \square ? \quad (5) \implies |-3| +1 \quad \square ? \quad (5)\\ \quad \\ \implies 3 +1 \quad \square ? \quad (5) \implies 4 \quad \square ? \quad 5\\ \textit{well, 4 is clearly less than 5, recall we have to use} \le \ or \ \ge\\ 4 \quad \square ? \quad 5 \implies 4 \le 5\\ \textit{so our sign is } \le\\ | x - 5 | +1 \quad \square ? \quad y \implies \color{blue}{| x - 5 | +1 \quad \le \quad y} \) still less than 5 anyhow

OpenStudy (anonymous):

So that's the answer?

OpenStudy (jdoe0001):

yeap, that's the inequality

OpenStudy (anonymous):

Thank you!

OpenStudy (jdoe0001):

yw

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